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- /*
- * This file is part of the MicroPython project, http://micropython.org/
- *
- * The MIT License (MIT)
- *
- * Copyright (c) 2013, 2014 Damien P. George
- * Copyright (c) 2015 Daniel Campora
- *
- * Permission is hereby granted, free of charge, to any person obtaining a copy
- * of this software and associated documentation files (the "Software"), to deal
- * in the Software without restriction, including without limitation the rights
- * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
- * copies of the Software, and to permit persons to whom the Software is
- * furnished to do so, subject to the following conditions:
- *
- * The above copyright notice and this permission notice shall be included in
- * all copies or substantial portions of the Software.
- *
- * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
- * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
- * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
- * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
- * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
- * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
- * THE SOFTWARE.
- */
- #include "py/obj.h"
- #include "lib/timeutils/timeutils.h"
- // LEAPOCH corresponds to 2000-03-01, which is a mod-400 year, immediately
- // after Feb 29. We calculate seconds as a signed integer relative to that.
- //
- // Our timebase is relative to 2000-01-01.
- #define LEAPOCH ((31 + 29) * 86400)
- #define DAYS_PER_400Y (365*400 + 97)
- #define DAYS_PER_100Y (365*100 + 24)
- #define DAYS_PER_4Y (365*4 + 1)
- STATIC const uint16_t days_since_jan1[]= { 0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334, 365 };
- bool timeutils_is_leap_year(mp_uint_t year) {
- return (year % 4 == 0 && year % 100 != 0) || year % 400 == 0;
- }
- // month is one based
- mp_uint_t timeutils_days_in_month(mp_uint_t year, mp_uint_t month) {
- mp_uint_t mdays = days_since_jan1[month] - days_since_jan1[month - 1];
- if (month == 2 && timeutils_is_leap_year(year)) {
- mdays++;
- }
- return mdays;
- }
- // compute the day of the year, between 1 and 366
- // month should be between 1 and 12, date should start at 1
- mp_uint_t timeutils_year_day(mp_uint_t year, mp_uint_t month, mp_uint_t date) {
- mp_uint_t yday = days_since_jan1[month - 1] + date;
- if (month >= 3 && timeutils_is_leap_year(year)) {
- yday += 1;
- }
- return yday;
- }
- void timeutils_seconds_since_2000_to_struct_time(mp_uint_t t, timeutils_struct_time_t *tm) {
- // The following algorithm was adapted from musl's __secs_to_tm and adapted
- // for differences in MicroPython's timebase.
- mp_int_t seconds = t - LEAPOCH;
- mp_int_t days = seconds / 86400;
- seconds %= 86400;
- if (seconds < 0) {
- seconds += 86400;
- days -= 1;
- }
- tm->tm_hour = seconds / 3600;
- tm->tm_min = seconds / 60 % 60;
- tm->tm_sec = seconds % 60;
- mp_int_t wday = (days + 2) % 7; // Mar 1, 2000 was a Wednesday (2)
- if (wday < 0) {
- wday += 7;
- }
- tm->tm_wday = wday;
- mp_int_t qc_cycles = days / DAYS_PER_400Y;
- days %= DAYS_PER_400Y;
- if (days < 0) {
- days += DAYS_PER_400Y;
- qc_cycles--;
- }
- mp_int_t c_cycles = days / DAYS_PER_100Y;
- if (c_cycles == 4) {
- c_cycles--;
- }
- days -= (c_cycles * DAYS_PER_100Y);
- mp_int_t q_cycles = days / DAYS_PER_4Y;
- if (q_cycles == 25) {
- q_cycles--;
- }
- days -= q_cycles * DAYS_PER_4Y;
- mp_int_t years = days / 365;
- if (years == 4) {
- years--;
- }
- days -= (years * 365);
- /* We will compute tm_yday at the very end
- mp_int_t leap = !years && (q_cycles || !c_cycles);
- tm->tm_yday = days + 31 + 28 + leap;
- if (tm->tm_yday >= 365 + leap) {
- tm->tm_yday -= 365 + leap;
- }
- tm->tm_yday++; // Make one based
- */
- tm->tm_year = 2000 + years + 4 * q_cycles + 100 * c_cycles + 400 * qc_cycles;
- // Note: days_in_month[0] corresponds to March
- STATIC const int8_t days_in_month[] = {31, 30, 31, 30, 31, 31, 30, 31, 30, 31, 31, 29};
- mp_int_t month;
- for (month = 0; days_in_month[month] <= days; month++) {
- days -= days_in_month[month];
- }
- tm->tm_mon = month + 2;
- if (tm->tm_mon >= 12) {
- tm->tm_mon -= 12;
- tm->tm_year++;
- }
- tm->tm_mday = days + 1; // Make one based
- tm->tm_mon++; // Make one based
- tm->tm_yday = timeutils_year_day(tm->tm_year, tm->tm_mon, tm->tm_mday);
- }
- // returns the number of seconds, as an integer, since 2000-01-01
- mp_uint_t timeutils_seconds_since_2000(mp_uint_t year, mp_uint_t month,
- mp_uint_t date, mp_uint_t hour, mp_uint_t minute, mp_uint_t second) {
- return
- second
- + minute * 60
- + hour * 3600
- + (timeutils_year_day(year, month, date) - 1
- + ((year - 2000 + 3) / 4) // add a day each 4 years starting with 2001
- - ((year - 2000 + 99) / 100) // subtract a day each 100 years starting with 2001
- + ((year - 2000 + 399) / 400) // add a day each 400 years starting with 2001
- ) * 86400
- + (year - 2000) * 31536000;
- }
- mp_uint_t timeutils_mktime(mp_uint_t year, mp_int_t month, mp_int_t mday,
- mp_int_t hours, mp_int_t minutes, mp_int_t seconds) {
- // Normalize the tuple. This allows things like:
- //
- // tm_tomorrow = list(time.localtime())
- // tm_tomorrow[2] += 1 # Adds 1 to mday
- // tomorrow = time.mktime(tm_tomorrow)
- //
- // And not have to worry about all the weird overflows.
- //
- // You can subtract dates/times this way as well.
- minutes += seconds / 60;
- if ((seconds = seconds % 60) < 0) {
- seconds += 60;
- minutes--;
- }
- hours += minutes / 60;
- if ((minutes = minutes % 60) < 0) {
- minutes += 60;
- hours--;
- }
- mday += hours / 24;
- if ((hours = hours % 24) < 0) {
- hours += 24;
- mday--;
- }
- month--; // make month zero based
- year += month / 12;
- if ((month = month % 12) < 0) {
- month += 12;
- year--;
- }
- month++; // back to one based
- while (mday < 1) {
- if (--month == 0) {
- month = 12;
- year--;
- }
- mday += timeutils_days_in_month(year, month);
- }
- while ((mp_uint_t)mday > timeutils_days_in_month(year, month)) {
- mday -= timeutils_days_in_month(year, month);
- if (++month == 13) {
- month = 1;
- year++;
- }
- }
- return timeutils_seconds_since_2000(year, month, mday, hours, minutes, seconds);
- }
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